Question on: WAEC Physics - 2009
A cell of e.m.f. 1.5V is connected in series with a resistor of resistance 3.0\(\Omega\). A voltmeter connected across the cell registers 0.9V. Calculate the internal resistance of the cell
A
2.0\(\Omega\).
B
3.0\(\Omega\).
C
5.0\(\Omega\).
D
6.0\(\Omega\).
Ask EduPadi AI for a detailed answer
Correct Option: A
\(\frac{V}{R} = \frac{E}{R + r}\)
\(\frac{0.9}{3} = \frac{1.5}{3 + r}\)
r = 2\(\Omega\).
\(\frac{0.9}{3} = \frac{1.5}{3 + r}\)
r = 2\(\Omega\).
Add your answer
Please share this, thanks!
No responses